Skip like a rabbit!

Erik the Outgolfer 08/26/2017. 30 answers, 2.887 views
code-golf array-manipulation

Given a list of non-negative integers in any reasonable format, iterate over it, skipping as many elements as every integer you step on says.


Here is a worked example:

[0, 1, 0, 2, 5, 1, 3, 1, 6, 2] | []
 ^ First element, always include it
[0, 1, 0, 2, 5, 1, 3, 1, 6, 2] | [0]
    ^ Skip 0 elements
[0, 1, 0, 2, 5, 1, 3, 1, 6, 2] | [0, 1]
          ^ Skip 1 element
[0, 1, 0, 2, 5, 1, 3, 1, 6, 2] | [0, 1, 2]
                   ^ Skip 2 elements
[0, 1, 0, 2, 5, 1, 3, 1, 6, 2] | [0, 1, 2, 3]
Skip 3 elements; you're done

Another worked example, not so all-equal-deltas:

[4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2] | []
 ^ First element, always include it
[4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2] | [4]
                ^ Skip 4 elements
[4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2] | [4, 3]
                            ^ Skip 3 elements
[4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2] | [4, 3, 3]
                                        ^ Skip 3 elements
[4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2] | [4, 3, 3, 4]
Skip 4 elements; you're done

An out-of-bounds example:

[0, 2, 0, 2, 4, 1, 2] | []
^ First element, always include it
[0, 2, 0, 2, 4, 1, 2] | [0]
    ^ Skip 0 elements
[0, 2, 0, 2, 4, 1, 2] | [0, 2]
             ^ Skip 2 elements
[0, 2, 0, 2, 4, 1, 2] | [0, 2, 4]
Skip 4 elements; you're done (out of bounds)

Rules

  • You may not use any boring cheat among these ones, they make the challenge boring and uninteresting.
  • You should only return/print the final result. STDERR output is ignored.
  • You may not get the input as a string of digits in any base (e.g. "0102513162" for the first case).
  • You must use left-to-right order for input.
  • As in the worked examples, if you go out of bounds, execution terminates as if otherwise.
  • You should use 0 for skipping 0 elements.
  • Given the empty list ([]) as input, you should return [].

Test cases

[]                                                     => []
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]                     => [0, 1, 3, 7]
[5, 1, 2, 3, 4, 5, 2, 1, 2, 1, 0, 0]                   => [5, 2, 1, 0]
[0, 1, 0, 2, 5, 1, 3, 1, 6, 2]                         => [0, 1, 2, 3]
[4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2] => [4, 3, 3, 4]
[0, 2, 0, 2, 4, 1, 2]                                  => [0, 2, 4]

This is , so shortest answer wins!

5 Comments
Erik the Outgolfer 07/28/2017
Sandbox (2k+ users only)
3 Shaggy 07/28/2017
Yeah, just spotted it. /puts glasses on
2 Rod 07/28/2017
Probably a leprechaun ¯\_(ツ)_/¯
1 Roman Gräf 07/28/2017
Is it okay to have trailing zeros in my array? would save me ~18 bytes
1 Erik the Outgolfer 07/28/2017
@RomanGräf Sorry but no, that would be too ambiguous since there are cases you should have trailing 0s in the output.

30 Answers


Rod 07/28/2017.

Python 2, 36 bytes

f=lambda x:x and x[:1]+f(x[x[0]+1:])

Try it online!

4 comments
Mr. Xcoder 07/28/2017
I was expecting to get outgolfed, but not that badly :)
Erik the Outgolfer 07/28/2017
Can't you do x[0] instead of x[:1]?
Rod 07/28/2017
@EriktheOutgolfer yes, but it need to be a list, so it would be [x[0]]
Erik the Outgolfer 07/28/2017
@Rod You're not saving any bytes with x[:1] anyways...f=lambda x:x and[x[0]]+f(x[x[0]+1:])

Mr. Xcoder 08/19/2017.

Python 2, 49 46* 41 bytes

Crossed out 4 is still regular 4 :(

* -3 thanks to @ASCII-only.

l=input()
while l:print l[0];l=l[l[0]+1:]

Try it online!

Prints the results separated by a newline, as the OP allowed in chat. I don't think it can get any shorter as a non-recursive full program.


How does this work?

  • l=input() - Reads the list from the standard input.

  • while l: - Abuses the fact that empty lists are falsy in Python, loops until the list is empty.

  • print l[0]; - Prints the first element of the list.

  • l=l[l[0]+1:] - "Skips like a rabbit" - Trims the first l[0]+1 from the list.

Let's take an example

Given the list [5, 1, 2, 3, 4, 5, 2, 1, 2, 1, 0, 0] as input, the code performs the following (according to the explanation above) - Prints the first item of the array: 5, trim the first 6: [2, 1, 2, 1, 0, 0]. We then print 2 and trim the first 3: [1,0,0]. Likewise, we output 1, crop the first 2, and we get [0]. Of course, 0 is printed and the program terminates.

1 comments

w0lf 07/28/2017.

Haskell, 29 27 26 bytes

j(x:y)=x:j(drop x y)
j x=x

Saved 1 byte thanks to Zgarb.

Try it online.

2 comments
Zgarb 07/28/2017
f x=x on the second line saves a byte.
w0lf 07/28/2017
@Zgarb Cool, thanks!

Adnan 07/28/2017.

05AB1E, 10 9 bytes

[¬Dg>#=ƒ¦

Uses the 05AB1E encoding. Try it online!

1 comments
Magic Octopus Urn 07/28/2017
Yeah, that is way better than what I was thinking.

Martin Ender 07/28/2017.

Mathematica, 46 44 bytes

SequenceCases[#,{x_,y___}/;Tr[1^{y}]<=x:>x]&

Alternatives:

SequenceCases[#,{x_,y___}/;x>=Length@!y:>x]&
SequenceCases[#,l:{x_,___}/;x>Tr[1^l]-2:>x]&
1 comments
Mr.Wizard 07/28/2017
Wow, that's great!

Johan Karlsson 07/28/2017.

JavaScript (ES6), 42 39 35 bytes

a=>a.map((n,i)=>a.splice(i+1,n))&&a

let f = 
a=>a.map((n,i)=>a.splice(i+1,n))&&a

console.log(f([]))                                                     // => []
console.log(f([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]))                     // => [0, 1, 3, 7]
console.log(f([5, 1, 2, 3, 4, 5, 2, 1, 2, 1, 0, 0]))                   // => [5, 2, 1, 0]
console.log(f([0, 1, 0, 2, 5, 1, 3, 1, 6, 2]))                         // => [0, 1, 2, 3]
console.log(f([4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2])) // => [4, 3, 3, 4]
console.log(f([0, 2, 0, 2, 4, 1, 2]))                                  // => [0, 2, 4]

Old Solution 39 Bytes

a=>a.map(n=>i--||r.push(i=n),r=i=[])&&r

-3 bytes thanks to @ThePirateBay

1 comments
ThePirateBay 07/28/2017
39 bytes a=>a.map(n=>i--||r.push(i=n),r=i=[])&&r

TheLethalCoder 07/28/2017.

C#, 68 bytes

a=>{for(int i=0;i<a.Count;i+=a[i]+1)System.Console.Write(a[i]+" ");}

Try it online!

Full/Formatted version:

namespace System
{
    class P
    {
        static void Main()
        {
            Action<Collections.Generic.List<int>> f = a =>
            {
                for (int i = 0; i < a.Count; i += a[i] + 1)
                    System.Console.Write(a[i] + " ");
            };

            f(new Collections.Generic.List<int>() { });Console.WriteLine();
            f(new Collections.Generic.List<int>() { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 });Console.WriteLine();
            f(new Collections.Generic.List<int>() { 5, 1, 2, 3, 4, 5, 2, 1, 2, 1, 0, 0 });Console.WriteLine();
            f(new Collections.Generic.List<int>() { 0, 1, 0, 2, 5, 1, 3, 1, 6, 2 });Console.WriteLine();
            f(new Collections.Generic.List<int>() { 4, 5, 1, 3, 8, 3, 0, 1, 1, 3, 1, 2, 7, 4, 0, 0, 1, 2 });Console.WriteLine();
            f(new Collections.Generic.List<int>() { 0, 2, 0, 2, 4, 1, 2 });Console.WriteLine();

            Console.ReadLine();
        }
    }
}

Returning a list is longer at 107 bytes.

a=>{var l=new System.Collections.Generic.List<int>();for(int i=0;i<a.Count;i+=a[i]+1)l.Add(a[i]);return l;}
3 comments
2 TheLethalCoder 07/28/2017
Why has someone downvoted this?
Thomas Ayoub 07/31/2017
To round your score and make a perfect 5k?
TheLethalCoder 07/31/2017
@ThomasAyoub We can only assume it was someone with OCD yes.

Zgarb 07/28/2017.

Husk, 8 6 bytes

←TU¡Γ↓

Try it online!

-2 bytes (and a completely new solution idea) thanks to Leo!

Explanation

I'm using the list pattern match function Γ. It takes a function f and a list with head x and tail xs, and applies f to x and xs. If the list is empty, Γ returns a default value consistent with its type, in this case an empty list. We take f to be , which drops x elements from xs. This function is then iterated and the resulting elements are collected in a list.

←TU¡Γ↓  Implicit input, e.g. [0,2,0,2,4,1,2]
    Γ↓  Pattern match using drop
   ¡    iterated infinitely: [[0,2,0,2,4,1,2],[2,0,2,4,1,2],[4,1,2],[],[],[],...
  U     Cut at first repeated value: [[0,2,0,2,4,1,2],[2,0,2,4,1,2],[4,1,2],[]]
 T      Transpose: [[0,2,4],[2,0,1],[0,2,2],[2,4],[4,1],[1,2],[2]]
←       First element: [0,2,4]
5 comments
Leo 07/28/2017
You can drop the default value of ø, and everything will still magically work :)
Zgarb 07/28/2017
@Leo Oh wow, that's clever!
Erik the Outgolfer 07/28/2017
Why did you CW this?
Zgarb 07/28/2017
@ErikTheOutgolfer That was a mistake (I'm on my phone and apparently pushed something by accident). I'm trying to undo it...

Ruud 07/28/2017.

Python 2, 59 55 bytes

l=input()
i=0
while l[i:]:i+=1;l[i:i+l[i-1]]=[]
print l

Try it online!

2 comments
1 Rod 07/28/2017
You can use l[i:i+l[i-1]]=[] instead del l[i:i+l[i-1]] to save a byte
1 ASCII-only 07/28/2017

Dave 07/28/2017.

Pyth, 22 Bytes

VQ aY.(Q0VeY .x.(Q0 ;Y

Removed a useless byte

4 comments
Erik the Outgolfer 07/28/2017
I see 23 bytes there.
Dave 07/28/2017
Typo :) sorry...
3 Wheat Wizard 07/28/2017
I'm not sure why you have a down vote. There is a possibility that when you edited fixing your answer this triggered an "automatic down vote". The reasons for this automatic downvote are confusing and terrible but it happens if the system considers your answer to be "low quality" based on it heuristics. Its also possible that someone didn't like your answer, but I don't see anything wrong with it at the moment so I'm not sure why that would be the case.
isaacg 07/31/2017
I'm glad you're using Pyth!

Rod 07/28/2017.

Python 2, 60 42 bytes

-18 bytes thanks to Luis Mendo

x=input()
i=0
while 1:print x[i];i+=1+x[i]

Try it online!


Martin Ender 07/28/2017.

Retina, 36 bytes

Byte count assumes ISO 8859-1 encoding.

.+
$*
((1)*¶)(?<-2>1*¶)*
$1
%M`.
0$

Input and output are linefeed-separated with a trailing linefeed.

Try it online! (Uses commas instead of linefeeds to allow for convenient test suites.)


Riley 07/28/2017.

Brain-Flak, 64 bytes

([]){{}(({})<>)<>{({}[()]<{}>)}{}([])}{}<>([]){{}({}<>)<>([])}<>

Try it online!

([]){{}                          ([])}{}                         # Until the stack is empty
       (({})<>)<>                                                # Copy TOS to off stack
                 {({}[()]<{}>)}{}                                # Pop TOS times
                                        <>([]){{}({}<>)<>([])}<> # Reverse off stack
2 comments
6 DJMcMayhem 07/28/2017
Holy crap! I wrote up a solution, and then scrolled down to post it, but it turns out we wrote the exact same solution byte-for-byte! Even minor details like ({}[()]<{}>) vs ({}<{}>[()]) were the same! What a coincidence!
2EZ 4RTZ 07/28/2017
@DJMcMayhem stealing all the fame XD

user202729 07/28/2017.

Mathematica, 64 50 bytes

±x_List:=Prepend[±Drop[x,1+#&@@x],#&@@x]
±_=±{}={}
1 comments
Mr.Wizard 07/28/2017
I couldn't resist further golfing this neat code; my answer is below.

jkelm 07/28/2017.

C# (.NET Core), 68 bytes

n=>{var t="";for(int i=0;i<n.Length;i+=n[i]+1)t+=n[i]+" ";return t;}

Try it online!

Takes input as an array of integers, returns a string containing the non-skipped values.

3 comments
TheLethalCoder 07/28/2017
Nice way to do it and comes in at the same count as printing.
jkelm 07/28/2017
I love the simple solutions. Still gotta learn LINQ though, as I have seen that shorten so many c# lambdas..
TheLethalCoder 07/28/2017
Shortens it because you can implicit return most of the time. Though it is a toss up between implicit return with using System.Linq; and a normal loop.

Jarko Dubbeldam 07/28/2017.

R, 58 bytes

f=function(x,p=1){cat(z<-x[p]);if(p+z<sum(x|1))f(x,p+z+1)}

Recursive function. Takes a vector x as argument and intiates a pointer p. This prints the corresponding entry of x, checks if p+x[p] would go out of bounds, and if not, calls the function for the new pointer.

f=function(x,p=1,s=x[1])`if`((z<-x[p]+p+1)>sum(x|1),s,f(x,z,c(s,x[z])))

This is a comparable solution that returns a proper vector instead of printing the digits.

3 comments
Giuseppe 07/28/2017
what about an input of numeric(0)? aka empty array.
Jarko Dubbeldam 07/28/2017
@Giuseppe I'll take a look at it when I'm behind my pc
Giuseppe 08/24/2017
57 bytes! and it handles the empty case as well.

Roman Gräf 07/28/2017.

Java (OpenJDK 8), 53 bytes

Thanks to @PunPun1000 and @TheLethalCoder

a->{for(int n=0;;n+=1+a[n])System.out.println(a[n]);}

Try it online!

5 comments
TheLethalCoder 07/28/2017
Would printing the results, like in my C# answer, save you anything?
Roman Gräf 07/28/2017
@TheLethalCoder Ill try
TheLethalCoder 07/28/2017
Can you save a byte by moving n into the loop?
TheLethalCoder 07/28/2017
Plus this doesn't seem to work at the moment.
PunPun1000 07/28/2017
You're missing a paren after the (a[n+=1+a[n]]. Function also throws an error after outputting the correct value, I don't know the concensus on whether this is allowed or not (the question does say anything to standard error is ignore). If that was the intention, then you can remove the n<a.length in the for loop. Finally the TIO code doesn't run as is, even with the paren. The function should be a Consumer<int[]> and use func.accept(test)

Martin Ender 07/28/2017.

Alice, 15 bytes

/$.. \h&
\I@nO/

Try it online!

Input and output a linefeed-separated lists of decimal integers.

Explanation

/   Switch to Ordinal mode.
I   Read a line.
.   Duplicate it.
n   Logical NOT (gives truthy if we're at EOF).
/   Switch to Cardinal.
    The IP wraps around to the left.
\   Switch to Ordinal.
$@  Terminate the program if we're at EOF.
.   Duplicate the input line again.
O   Print it.
\   Switch to Cardinal.
h   Increment the value.
&   Store the result in the iterator queue.
    The program wraps around to the beginning.

Storing an integer n in the iterator queue causes the next command to be executed n times. Mirrors like / are not commands, so the next command will be I. Therefore if we just read and printed a value x, we will read x+1 values on the next iteration, with the last of them ending up on top of the stack. This skips the required number list elements.


Mr.Wizard 07/28/2017.

Mathematica, 37 (30?)

Further golfing of user202729's fine method.

±{a_,x___}={a}~Join~±{x}~Drop~a
±_={}

The rules don't seem to explicitly specify the output format, so maybe:

±{a_,x___}=a.±{x}~Drop~a
±_={}

Output for the second function looks like: 0.2.4.{} — notably {} is still returned for an empty set, conforming to the final rule.

2 comments
1 JungHwan Min 07/28/2017
±Drop[{x},a] can be ±{x}~Drop~a because ± has a lower precedence than Infix.
Mr.Wizard 07/28/2017
@JungHwanMin I missed that; thanks!

Jenny_mathy 07/28/2017.

Mathematica, 65 bytes

(s=#;t=1;w={};While[t<=Length@s,AppendTo[w,k=s[[t]]];t=t+k+1];w)&

Try it online!


w0lf 07/28/2017.

Ruby, 36 33 31

f=->l{a,*l=l;a&&f[l.drop(p a)]}

Try it online.

4 comments
sethrin 07/30/2017
You're allowed to subtract the f= as a header element.
w0lf 07/30/2017
@sethrin Even if I need to call it recursively?
sethrin 07/30/2017
Hmm, good question. I suppose not. I did very much like that about your solution, by the way.
w0lf 07/30/2017
@sethrin Thanks! :)

AnonymousReality 07/28/2017.

Swift, 63 bytes

func a(d:[Int]){var i=0;while i<d.count{print(d[i]);i+=d[i]+1}}

This is my first entry, ever, so I'm not 100% sure on the rules, but hopefully this answer suffices. I'm a little unsure of rules on how to get the input into a system. I have a shorter answer if I was allowed to assume a function somewhere that can return the input.

2 comments
Stephen 07/28/2017
Welcome to PPCG! The default rules are that you can either have code that works as a full program, so input (usually) in STDIN and output (usually) to STDOUT, or a function, so input (usually) from function parameters and output (usually) from function return.
AnonymousReality 07/28/2017
@StepHen - thanks! I guess that makes my other version invalid then. Looking forward to contributing more!

Perl 6, 31 bytes

{(@_,{.[1+.[0]..*]}...^0)[*;0]}

Test it

Expanded:

{  # bare block lambda with implicit parameter 「@_」
  (
    # generate a sequence

    @_,

    {
      .[ # index into previous value in the sequence
        1 + .[0]  # start by skipping one plus the first element
                  # of the previous value in the sequence
        ..  *     # use that to create a Range with no end
      ]
    }

    ...^  # keep doing that until: (and throw away last value)
    0     # it generates an empty list

  )[ *; 0 ]  # from every value in the sequence, get the first element
}

To help understand how the code works, without [*;0] this would generate a sequence like the following:

[0, 1, 0, 2, 5, 1, 3, 1, 6, 2],
   (1, 0, 2, 5, 1, 3, 1, 6, 2),
         (2, 5, 1, 3, 1, 6, 2),
                  (3, 1, 6, 2)

Renzo 07/29/2017.

Common Lisp, 51 bytes

(do((x(read)(nthcdr(1+(print(car x)))x)))((not x)))

Try it online!


C++ (gcc), 172 bytes

#include<iostream>
int main(){std::istream& i=std::cin;char c;int a,b;while(i>>c&&i>>a){std::cout<<c<<(c/91?"":" ")<<a;while(a--&&i>>c&&i>>b);}std::cout<<c<<(c/93?"":"]");}

Try it online

The awful (c/91?"":" ") is for correct spacing in output. Without it (-15 bytes) output is in form: [0,2,4], when I change it to simple " " (-9 bytes) output is like [ 0, 2, 4] (additional space at the beginning).

<<(c/93?"":"]") on the end is only to handle [] empty input corner case

Prints no trailing endline.

1 comments
Erik the Outgolfer 07/30/2017
You can also print the numbers separated by a no-digit separator, no need for [] and you can have empty output for that edge-case, and no need for (c/91?"":" "). You don't have to match the format of the examples in the challenge.

Jonathan Allan 07/29/2017.

Jelly, 8 bytes

ḢṄ‘ṫ@µL¿

A full program printing the results each followed by a newline (empty list produces no output).

Try it online!

How?

ḢṄ‘ṫ@µL¿ - Main link: list of non-negative integers  e.g. [2,5,4,0,1,2,0]
       ¿ - while:           Iteration:  1                  2             3          4        5
      L  -   length (0 is falsey)       7                  4             3          1        0
     µ   - ...do:                                                                            stop
Ḣ        -   head (pop & modify)        2 ([5,4,0,1,2,0])  0 ([1,2,0])   1 ([2,0])  0 ([0])
 Ṅ       -   print it (and yield it)   "2\n"              "0\n"         "1\n"      "0\n"
  ‘      -   increment                  3                  1             2          1
   ṫ@    -   tail from index            [0,1,2,0]          [1,2,0]      [0]         []
         -
         -                       i.e. a resulting in the printing of: '''2
                                                                         0
                                                                         1
                                                                         0
                                                                         '''
2 comments
Erik the Outgolfer 07/30/2017
Finally a Jelly answer! BTW I can do it in 7 bytes.
Erik the Outgolfer 07/30/2017
And I also have a list-returning function in 18 bytes.

Evpok 07/30/2017.

Python 3, 35 bytes

f=lambda h=0,*t:t and[h,*f(*t[h:])]

Try it online!

Run it with f(*l) where l is your input. Arguably stretching the rules for input, but I just love advanced unpacking.


cliffroot 07/28/2017.

Clojure, 67 bytes

#(nth(reduce(fn[[z k]b](if(= z 0)[b(conj k b)][(- z 1)k]))[0[]]%)1)

Starts with the initial parameters [0 []], where 0 is the counter and [] is the result. If the first element in this list is 0 appends item n from the argument to the result and passes further this list [n [... n]] otherwise decrements the first element. (this explanation feels horrible to me)

See it online


Dead Possum 07/28/2017.

Python 2.4, 85 bytes

No chance to win in python with it, but I love oneliners and this one might be interesting to others.
Turns out, there is a fancy magic trick to access building list inside comprehension, but it works only in 2.4 and with some edits in <= 2.3
locals()['_[1]'] it is. Python creates secret name _[1] for list, while it is created and store it in locals. Also names _[2], _[3]... are used for nested lists.

lambda n:[j for i,j in enumerate(n)if i==len(locals()['_[1]'])+sum(locals()['_[1]'])]

So it counts number of already added elements plus their sum. Result is the index of next desired element.
I think, that there should be a way to avoid enumerate. Like accessing input array directly by index: [ n[len(locals()['_[1]'])+sum(locals()['_[1]'])] for ... ]. But I can't figure out a compact way to protect it from index-out-of-range (while keeping it oneliner)

enter image description here


Neil 07/28/2017.

Batch, 69 bytes

:l
@if not "%1"=="" echo %1&(for /l %%i in (0,1,%1)do @shift)&goto l

(I need the ()s around the for otherwise the goto happens inside the loop.)


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10 Fitz And The Tantrums

HandClap flac

Fitz And The Tantrums. 2017. Writer: Fitz And The Tantrums;Eric Frederic;Sam Hollander.
11 Backstreet Boys

Chances flac

Backstreet Boys. 2018.
12 Kelly Clarkson

Never Enough flac

Kelly Clarkson. 2018. Writer: Benj Pasek;Justin Paul.
13 Diplo

Close To Me flac

Diplo. 2018. Writer: Ellie Goulding;Savan Kotecha;Peter Svensson;Ilya;Swae Lee;Diplo.
14 Anne-Marie

Rewrite The Stars flac

Anne-Marie. 2018. Writer: Benj Pasek;Justin Paul.
15 Little Mix

Woman Like Me flac

Little Mix. 2018. Writer: Nicki Minaj;Steve Mac;Ed Sheeran;Jess Glynne.
16 Imagine Dragons

Machine flac

Imagine Dragons. 2018. Writer: Wayne Sermon;Daniel Platzman;Dan Reynolds;Ben McKee;Alex Da Kid.
17 Little Mix

The Cure flac

Little Mix. 2018.
18 Bradley Cooper

Always Remember Us This Way flac

Bradley Cooper. 2018. Writer: Lady Gaga;Dave Cobb.
19 Rita Ora

Velvet Rope flac

Rita Ora. 2018.
20 Lady Gaga

I'll Never Love Again flac

Lady Gaga. 2018. Writer: Benjamin Rice;Lady Gaga.

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